7x^2+14x=245

Solution for 7x^2+14x=245 equation:

7x^2+14x=245

We move all terms to the left:

7x^2+14x-(245)=0

a = 7; b = 14; c = -245;
Δ = b2-4ac
Δ = 142-4·7·(-245)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-84}{2*7}=\frac{-98}{14}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+84}{2*7}=\frac{70}{14}
=5
$